Wednesday 6 September 2017

C-Program to Covert Binary to Octal


#include<stdio.h>

int main()
{
 int octalNum[]={0,1,10,11,100,101,110,111};
 long int binary,i,number,temp,octal=0,j=1;
 printf("Enter Binary number\n");
 scanf("%ld",&binary);
 temp=binary;
 while(temp!=0)
 {
  number=temp%1000;
  for(i=0;i<=7;i++)
  {
   if(octalNum[i]==number)
   {
    octal=octal+(i*j);
   }
  }
  j*=10;
  temp/=1000;
 }
 printf("Octal number for given Binary number %ld is %ld\n",binary,octal);
return 0;
}

Method II:
#include<stdio.h>
#include<math.h>
int ConvertFromBinarytoOther(int);
int ConvertFromDecimalToOther(int);

int main()
{
 int final,num,binary,decimal;
 printf("Enter Binary Number\n");
 scanf("%d",&binary);
 decimal=ConvertFromBinarytoOther(binary);//Converting binary to decimal
 final=ConvertFromDecimalToOther(decimal);//Converting decimal to octal
 //So binary to Octal
 printf("Octal number of Binary number %d is %d\n",binary,final);
return(0);
}

int ConvertFromDecimalToOther(int decimal)
{
 int temp,i,j=1,final=0;
    temp=decimal;
    while(temp!=0)
    {
      i=temp%8;
      final=final+(i*j);
      temp=temp/8;
      j=j*10;
     }
     return(final);
}

int ConvertFromBinarytoOther(int binary)
{
 int final=0,i,inc=0,temp;
    temp=binary;
    while(temp!=0)
    {
      i=temp%10;
      final=final+(i*pow(2,inc));
      temp=temp/10;
      inc++;
     }
     return(final);
}

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